In this topic, you learned how to perform equality match and only those document that satisfies the condition in MongoDB. Instead, you would want to group on distinct values counting the amount of times that value exists, at which point you could easily add a stage to sum. The MongoDB aggregation pipeline consists of stages. Just saw this, it would not count distinct objects at all, instead it will place, distinctly, objects into an array, not only that but distinction would be on which is not always a good idea. The following example runs a db.collection.

To run an operation in the embedded MongoDB Shell, type the operation into the shell and press Enter.

To use a different database, run the following command in mongosh: use .

There are 3 ways to perform aggregation operations:ĭocuments enter into a multi-stage pipeline that converts the documents into an aggregated result. By default, mongosh, connects to the test database. You can use the following methods to count the distinct values in a specific field in MongoDB: Method 1: Find List of Distinct Values. SUM shows the total sum of the values in a numeric field. The following SQL query shows the number of customers per city in ascending order: select count(), address.city from Customers group by address.city order by count() SUM. It is an operation that is used to process the data and it consists of the stages that perform a number of operations on the grouped data to return a single result. COUNT shows the numerical count of documents that match the query criteria. MongoDB group and count with the condition.MongoDB group by count greater than 1 (any number).

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